What is the tangent of y=(4/(x+2)),\at x=2 ?

The tangent of y=(4/(x+2)),\at x=2 is y=-1/4 x+3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(4/(x+2)),\at x=2

tangent of

y = (\frac{4}{x + 2}), at x = 2

y = - \frac{1}{4} x + \frac{3}{2}

Solution steps

Find the tangent point:

(2, 1)

Find the slope of

y = \frac{4}{x + 2} : \frac{d y}{d x} = - \frac{4}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(2, 1) : y = - \frac{1}{4} x + \frac{3}{2}

y = - \frac{1}{4} x + \frac{3}{2}

\int \frac{6}{7} sec^{2} (\frac{x}{7}) d x

\int \frac{e ^{3 - x}}{( 1 + e ^{3 - x} ) ^{2}} d x

y^{^{''}} + 8 y^{^{'}} + 65 y = 0

x \to 0 - lim (\frac{x}{13 x ^{4} - 6 x})

\frac{\partial}{\partial y} (x yz)

What is the tangent of y=(4/(x+2)),\at x=2 ?
The tangent of y=(4/(x+2)),\at x=2 is y=-1/4 x+3/2