What is the solution for xy^2y^'=y^3-3x^3,y(1)=6 ?

The solution for xy^2y^'=y^3-3x^3,y(1)=6 is y=\sqrt[3]{9}x\sqrt[3]{-ln(x)+24}

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xy^2y^'=y^3-3x^3,y(1)=6

x y^{2} y^{^{'}} = y^{3} - 3 x^{3}, y (1) = 6

y = 39 x 3 - ln (x) + 24

Solution steps

x y^{2} y^{'} (x) = y^{3} - 3 x^{3}

Solve Bernoulli ODE:

y = 39 x 3 - ln (x) + 24

y = 39 x 3 - ln (x) + 24

x = 8 y^{2}, x = 2 + 6 y^{2}

x \to - \infty lim (1 0^{x})

\frac{\partial}{\partial x} (x^{- 3} y^{2} + x y^{2} + 5 x y)

\int \frac{1}{x - a} d x

\frac{8}{( z ^{2} + 4 ) ^{2}}

What is the solution for xy^2y^'=y^3-3x^3,y(1)=6 ?
The solution for xy^2y^'=y^3-3x^3,y(1)=6 is y=\sqrt[3]{9}x\sqrt[3]{-ln(x)+24}