What is the limit as x approaches 0 of ((x^2+4x))/x ?

The limit as x approaches 0 of ((x^2+4x))/x is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ((x^2+4x))/x

x \to 0 lim (\frac{( x ^{2} + 4 x )}{x})

4

Solution steps

x \to 0 lim (\frac{x ^{2} + 4 x}{x})

Simplify

\frac{x ^{2} + 4 x}{x} : x + 4

= x \to 0 lim (x + 4)

Plug in the value

x = 0

= 0 + 4

Simplify

= 4

(3 x^{2} + y - 4) - (2 y - x) y^{^{'}} = 0

2 y \cdot \frac{d y}{d x} = - x^{2}

\frac{d}{d x} (x k)

(2, - 3), (0, 4)

\frac{d y}{d x}, x y = 4

What is the limit as x approaches 0 of ((x^2+4x))/x ?
The limit as x approaches 0 of ((x^2+4x))/x is 4