What is the integral from 0 to 7 of xe^{-x} ?

The integral from 0 to 7 of xe^{-x} is -8/(e^7)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 7 of xe^{-x}

\int_{0}^{7} x e^{- x} d x

- \frac{8}{e ^{7}} + 1

Decimal

0.99270 \dots

Solution steps

\int_{0}^{7} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{7}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{7}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{7}

Compute the boundaries:

- \frac{8}{e ^{7}} + 1

= - \frac{8}{e ^{7}} + 1

x^{2} - 1, - x + 2, 0, 1

x \to \infty lim (x ln (x))

f (x) = ((18 x (x^{2} + 6)^{8}))

\frac{d}{d x} (\frac{- cos ( x )}{4 x ^{2} + 2 x - 3})

\frac{d y}{d t} + 2 y = 3 t^{2} + 2 t - 1

What is the integral from 0 to 7 of xe^{-x} ?
The integral from 0 to 7 of xe^{-x} is -8/(e^7)+1