What is (\partial)/(\partial x)(x-xy+3) ?

The answer to (\partial)/(\partial x)(x-xy+3) is -y+1

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(\partial)/(\partial x)(x-xy+3)

\frac{\partial}{\partial x} (x - x y + 3)

- y + 1

Solution steps

\frac{\partial}{\partial x} (x - x y + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (3) = 0

= 1 - y + 0

Simplify

= - y + 1

\int_{4}^{9} \frac{t - 3}{t} d t

x \to 0 lim (cos^{2} (5 x))

x \to - \infty lim (6)

\int (\frac{1}{x}) d x

\frac{d}{d x} (2^{x} + x^{2})

What is (\partial)/(\partial x)(x-xy+3) ?
The answer to (\partial)/(\partial x)(x-xy+3) is -y+1