What is the derivative of (-2/((6x-7x^4)^3)) ?

The derivative of (-2/((6x-7x^4)^3)) is (6(6-28x^3))/((6x-7x^4)^4)

What is the first derivative of (-2/((6x-7x^4)^3)) ?

The first derivative of (-2/((6x-7x^4)^3)) is (6(6-28x^3))/((6x-7x^4)^4)

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Popular >

\frac{d}{d x} (\frac{- 2}{( 6 x - 7 x ^{4} ) ^{3}})

\frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{- 2}{( 6 x - 7 x ^{4} ) ^{3}})

Simplify

\frac{- 2}{( 6 x - 7 x ^{4} ) ^{3}} : - \frac{2}{( 6 x - 7 x ^{4} ) ^{3}}

= \frac{d}{d x} (- \frac{2}{( 6 x - 7 x ^{4} ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{1}{( 6 x - 7 x ^{4} ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d x} ((6 x - 7 x^{4})^{- 3})

Apply the chain rule:

- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} \frac{d}{d x} (6 x - 7 x^{4})

= - \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} \frac{d}{d x} (6 x - 7 x^{4})

\frac{d}{d x} (6 x - 7 x^{4}) = 6 - 28 x^{3}

= - 2 (- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} (6 - 28 x^{3}))

Simplify

- 2 (- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} (6 - 28 x^{3})) : \frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

= \frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

\int (\frac{8}{x} + 8 x) d x

\frac{d}{d x} (x sec (x) tan (x))

f (x) = x + \frac{9}{x}

\frac{\partial}{\partial x} ((x y)^{z})

\int \frac{x ^{3} - x ^{2} - 4 x + 4}{x ^{3} - x ^{2} - 6 x} d x

What is the derivative of (-2/((6x-7x^4)^3)) ?
The derivative of (-2/((6x-7x^4)^3)) is (6(6-28x^3))/((6x-7x^4)^4)
What is the first derivative of (-2/((6x-7x^4)^3)) ?
The first derivative of (-2/((6x-7x^4)^3)) is (6(6-28x^3))/((6x-7x^4)^4)