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Popular >

y^'+(y^2)/x =-1/x

Solution

y^{^{'}} + \frac{y ^{2}}{x} = - \frac{1}{x}

Solution

y = tan (- ln (x) + c_{1})

Solution steps

y^{'} (x) + \frac{y ^{2}}{x} = - \frac{1}{x}

Solve separable ODE:

y = tan (- ln (x) + c_{1})

y = tan (- ln (x) + c_{1})

Graph

Popular Examples

integral of (x^2-1)/(x^2+x)

\int \frac{x ^{2} - 1}{x ^{2} + x} d x

deg2rad (x'')^'degrees to radians

(x^{''})^{^{'}}

y^{''}+a*y^'=b,y(0)=0,y^'(0)=0

y^{^{''}} + a \cdot y^{^{'}} = b, y (0) = 0, y^{^{'}} (0) = 0

(dy)/(dx)=((2x+sec^2(x)))/(2y),y(0)=-6

\frac{d y}{d x} = \frac{( 2 x + sec ^{2} ( x ) )}{2 y}, y (0) = - 6

integral of (3x+5)/(x^2+1)

\int \frac{3 x + 5}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+(y^2)/x =-1/x ?
The solution for y^'+(y^2)/x =-1/x is y=tan(-ln(x)+c_{1})