What is the tangent of f(x)=(2x)/(x^2+1),\at x=1 ?

The tangent of f(x)=(2x)/(x^2+1),\at x=1 is y=1

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tangent of f(x)=(2x)/(x^2+1),\at x=1

tangent of

f (x) = \frac{2 x}{x ^{2} + 1}, at x = 1

y = 1

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{2 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, 1) : y = 1

y = 1

\int 2 x (x^{2} + 5)^{3} d x

x \to - 1 lim (\frac{6 x + 5}{5 x - 6})

\frac{\partial}{\partial x} \frac{10 3 ( 5 x ) ^{2}}{3}

\frac{d y}{d x} - \frac{2 y}{x} = x^{- 1} y^{- 1}

\int (\frac{c x}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}) d x

What is the tangent of f(x)=(2x)/(x^2+1),\at x=1 ?
The tangent of f(x)=(2x)/(x^2+1),\at x=1 is y=1