What is (\partial)/(\partial x)(2x^2-3xy+z-4) ?

The answer to (\partial)/(\partial x)(2x^2-3xy+z-4) is 4x-3y

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(\partial)/(\partial x)(2x^2-3xy+z-4)

\frac{\partial}{\partial x} (2 x^{2} - 3 x y + z - 4)

4 x - 3 y

Solution steps

\frac{\partial}{\partial x} (2 x^{2} - 3 x y + z - 4)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (3 x y) + \frac{\partial}{\partial x} (z) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (3 x y) = 3 y

\frac{\partial}{\partial x} (z) = 0

\frac{\partial}{\partial x} (4) = 0

= 4 x - 3 y + 0 - 0

Simplify

= 4 x - 3 y

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What is (\partial)/(\partial x)(2x^2-3xy+z-4) ?
The answer to (\partial)/(\partial x)(2x^2-3xy+z-4) is 4x-3y