What is the derivative of 9t-2t^2 ?

The derivative of 9t-2t^2 is 9-4t

What is the first derivative of 9t-2t^2 ?

The first derivative of 9t-2t^2 is 9-4t

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derivative of

9 t - 2 t^{2}

9 - 4 t

Solution steps

\frac{d}{d t} (9 t - 2 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (9 t) - \frac{d}{d t} (2 t^{2})

\frac{d}{d t} (9 t) = 9

\frac{d}{d t} (2 t^{2}) = 4 t

= 9 - 4 t

\int 4 x^{- 2} d x

\frac{d}{d x} (\frac{2 x}{1 - x})

x \to 3 lim (2 x^{2} - 3 x)

\frac{d y}{d x} = 2 x y

\frac{d}{d x} (\frac{( x - 1 ) ^{2}}{x + 2})

What is the derivative of 9t-2t^2 ?
The derivative of 9t-2t^2 is 9-4t
What is the first derivative of 9t-2t^2 ?
The first derivative of 9t-2t^2 is 9-4t