What is the integral of 2x(x^2+12)^3 ?

The integral of 2x(x^2+12)^3 is 1/4 (x^2+12)^4+C

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integral of 2x(x^2+12)^3

\int 2 x (x^{2} + 12)^{3} d x

\frac{1}{4} (x^{2} + 12)^{4} + C

Solution steps

\int 2 x (x^{2} + 12)^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} + 12)^{3} d x

Apply u-substitution

: \int \frac{u ^{3}}{2} d u

= 2 \cdot \int \frac{u ^{3}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= 2 \cdot \frac{1}{2} \cdot \frac{u ^{4}}{4}

Substitute back

u = x^{2} + 12

= 2 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 12 ) ^{4}}{4}

Simplify

2 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 12 ) ^{4}}{4} : \frac{1}{4} (x^{2} + 12)^{4}

= \frac{1}{4} (x^{2} + 12)^{4}

Add a constant to the solution

= \frac{1}{4} (x^{2} + 12)^{4} + C

\int (2 x + 1) e^{0.4 x} d x

\int_{- 1}^{3} (2 x^{3} - 10) d x

x \to 0 lim (\frac{- x ^{2}}{x})

\int_{0}^{4} \frac{1}{2 t + 1} d t

\int \frac{3}{( x - 1 ) ^{3}} d x

What is the integral of 2x(x^2+12)^3 ?
The integral of 2x(x^2+12)^3 is 1/4 (x^2+12)^4+C