What is inverse oflaplace 1/(s+2) ?

The answer to inverse oflaplace 1/(s+2) is e^{-2t}

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inverse oflaplace 1/(s+2)

inverse laplace

\frac{1}{s + 2}

e^{- 2 t}

Solution steps

L^{- 1} {\frac{1}{s + 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 2}} = e^{- 2 t}

= e^{- 2 t}

8 x + 6, x - x^{2}, - 6, - 1

\int_{- 3}^{3} \frac{14}{x ^{2} - 4 x - 45} d x

y = (3 x + 5) x^{2}

\int \frac{x ^{2} + 5 x + 6}{x + 3} d x

y = 9 - x^{2}, y = x + 3

What is inverse oflaplace 1/(s+2) ?
The answer to inverse oflaplace 1/(s+2) is e^{-2t}