What is the derivative of 2x+1/(x^2) ?

The derivative of 2x+1/(x^2) is 2-2/(x^3)

What is the first derivative of 2x+1/(x^2) ?

The first derivative of 2x+1/(x^2) is 2-2/(x^3)

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\frac{d}{d x} (2 x + \frac{1}{x ^{2}})

2 - \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (2 x + \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 2 - \frac{2}{x ^{3}}

s (t) = \frac{5}{4 t}

\frac{\partial}{\partial y} (e^{5 x y})

\int_{2}^{\infty} e^{- 8 p} d p

n = 1 \sum \infty (\frac{5}{9})^{n}

\int - \frac{1}{2} ln ∣ x ∣ - 8 x + 2 x^{2} + C^{1} d x

What is the derivative of 2x+1/(x^2) ?
The derivative of 2x+1/(x^2) is 2-2/(x^3)
What is the first derivative of 2x+1/(x^2) ?
The first derivative of 2x+1/(x^2) is 2-2/(x^3)