What is the sum from n=1 to infinity of (n-6)/(n+6) ?

The sum from n=1 to infinity of (n-6)/(n+6) is diverges

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sum from n=1 to infinity of (n-6)/(n+6)

n = 1 \sum \infty \frac{n - 6}{n + 6}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 6}{n + 6}

Apply Series Divergence Test:

diverges

= diverges

x y^{^{'}} + y + 4 = 0

\frac{\partial}{\partial x} (2 x e^{4 x y})

\int x^{3} (4 - x^{2})^{\frac{1}{4}} d x

\int_{0}^{1} x^{2} (x + 1)^{6} d x

\frac{6}{s ( s + 3 )}

What is the sum from n=1 to infinity of (n-6)/(n+6) ?
The sum from n=1 to infinity of (n-6)/(n+6) is diverges