en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^3+6x^2+8x,[-4,0]

Solution

area

x^{3} + 6 x^{2} + 8 x, [- 4, 0]

Solution

8

Solution steps

Apply the area formula:

\int_{- 4}^{0} x^{3} + 6 x^{2} + 8 x d x

Solve

\int_{- 4}^{0} x^{3} + 6 x^{2} + 8 x d x : 8

The area is:

= 8

Graph

Popular Examples

(\partial)/(\partial x)(-x^3-y^2+3x^2-10y-6)

\frac{\partial}{\partial x} (- x^{3} - y^{2} + 3 x^{2} - 10 y - 6)

integral of 1/((2-x))

\int \frac{1}{( 2 - x )} d x

integral of 1/(sqrt(3+x-x^2))

\int \frac{1}{3 + x - x ^{2}} d x

derivative of (x^3-2x+1)(3x^3+2x^2-5x)derivative of

(x^{3} - 2 x + 1) (3 x^{3} + 2 x^{2} - 5 x)

derivative of y=((x+1)^2)/(sqrt(x)+1)derivative of

y = \frac{( x + 1 ) ^{2}}{x + 1}

Frequently Asked Questions (FAQ)

What is area x^3+6x^2+8x,[-4,0] ?
The answer to area x^3+6x^2+8x,[-4,0] is 8