What is the sum from n=0 to infinity of (3/5)^n ?

The sum from n=0 to infinity of (3/5)^n is 5/2

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sum from n=0 to infinity of (3/5)^n

n = 0 \sum \infty (\frac{3}{5})^{n}

\frac{5}{2}

Solution steps

n = 0 \sum \infty (\frac{3}{5})^{n}

Apply Series Geometric Test:

\frac{5}{2}

= \frac{5}{2}

x \to + 3 - lim (\frac{3}{x - 3})

\int x \cdot 2^{x} d x

\int 4 cos (4 x) d x

y = cos^{7} (π t - 16)

\frac{d}{d x} (x^{5} + 4 x^{2} - 1)

What is the sum from n=0 to infinity of (3/5)^n ?
The sum from n=0 to infinity of (3/5)^n is 5/2