What is the sum from k=2 to infinity of 1/(k(ln(k))) ?

The sum from k=2 to infinity of 1/(k(ln(k))) is diverges

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sum from k=2 to infinity of 1/(k(ln(k)))

k = 2 \sum \infty \frac{1}{k ( ln ( k ) )}

diverges

Solution steps

k = 2 \sum \infty \frac{1}{k ln ( k )}

Apply Series Integral Test:

diverges

= diverges

- 6 x

\frac{d}{d y} (y^{2} e^{x y})

\frac{d}{d x} (x csc (x) - cot (x))

n = 0 \sum \infty \frac{6}{2 ^{n}}

f (x) = \frac{- 6}{x}

What is the sum from k=2 to infinity of 1/(k(ln(k))) ?
The sum from k=2 to infinity of 1/(k(ln(k))) is diverges