What is the solution for (dy}{dx}+\frac{2y)/x =2xy^{3/2} ?

The solution for (dy}{dx}+\frac{2y)/x =2xy^{3/2} is y= 1/(x^4-2c_{1)x^3+c_{1}^2x^2}

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(dy}{dx}+\frac{2y)/x =2xy^{3/2}

\frac{d y}{d x} + \frac{2 y}{x} = 2 x y^{\frac{3}{2}}

y = \frac{1}{x ^{4} - 2 c _{1} x ^{3} + c _{1}^{2} x ^{2}}

Solution steps

\frac{d y}{d x} + \frac{2 y}{x} = 2 x y^{\frac{3}{2}}

Solve Bernoulli ODE:

y = \frac{1}{x ^{4} - 2 c _{1} x ^{3} + c _{1}^{2} x ^{2}}

y = \frac{1}{x ^{4} - 2 c _{1} x ^{3} + c _{1}^{2} x ^{2}}

\int_{1}^{2} x - 1 d x

f (x) = 6 6 x^{10} + 7 x^{6}

(0, - 10), (5, - 6)

\frac{d}{d x} (arcsinh (cot (x)))

\frac{\partial}{\partial x} (y cos (z))

What is the solution for (dy}{dx}+\frac{2y)/x =2xy^{3/2} ?
The solution for (dy}{dx}+\frac{2y)/x =2xy^{3/2} is y= 1/(x^4-2c_{1)x^3+c_{1}^2x^2}