What is (\partial)/(\partial y)(y^2-cos(x)y) ?

The answer to (\partial)/(\partial y)(y^2-cos(x)y) is 2y-cos(x)

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(\partial)/(\partial y)(y^2-cos(x)y)

\frac{\partial}{\partial y} (y^{2} - cos (x) y)

2 y - cos (x)

Solution steps

\frac{\partial}{\partial y} (y^{2} - cos (x) y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) - \frac{\partial}{\partial y} (cos (x) y)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (cos (x) y) = cos (x)

= 2 y - cos (x)

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{3}{x ^{3}})

\frac{d}{d x} (∣ x ∣ + ∣ x - 1 ∣)

\frac{d}{d x} (x tan (2 x))

\frac{\partial}{\partial x} (sin (x^{3}))

x \to 3 + lim (\frac{2 x + 1}{x - 3})

What is (\partial)/(\partial y)(y^2-cos(x)y) ?
The answer to (\partial)/(\partial y)(y^2-cos(x)y) is 2y-cos(x)