What is the derivative of 4x^3-6x^2-72x ?

The derivative of 4x^3-6x^2-72x is 12x^2-12x-72

What is the first derivative of 4x^3-6x^2-72x ?

The first derivative of 4x^3-6x^2-72x is 12x^2-12x-72

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\frac{d}{d x} (4 x^{3} - 6 x^{2} - 72 x)

12 x^{2} - 12 x - 72

Solution steps

\frac{d}{d x} (4 x^{3} - 6 x^{2} - 72 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (72 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (72 x) = 72

= 12 x^{2} - 12 x - 72

\int (\frac{1}{x ^{7}}) d x

\int cos^{4} (7 x + 7) d x

y = 5 y^{2} (4 y^{2} + 7)^{\frac{6}{5}}

\frac{d y}{d x} = \frac{7 x}{3 y}

4 x^{2} + 2 x

What is the derivative of 4x^3-6x^2-72x ?
The derivative of 4x^3-6x^2-72x is 12x^2-12x-72
What is the first derivative of 4x^3-6x^2-72x ?
The first derivative of 4x^3-6x^2-72x is 12x^2-12x-72