What is the solution for (y-sqrt((x^2+y^2)))dx-xdy=0 ?

The solution for (y-sqrt((x^2+y^2)))dx-xdy=0 is y=-(x^2}{2e^{c_{1}}}+\frac{e^{c_{1}})/2

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(y-sqrt((x^2+y^2)))dx-xdy=0

(y - (x^{2} + y^{2})) d x - x d y = 0

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

Solution steps

(y - (x^{2} + y^{2})) d x - x d y = 0

Solve using substitution:

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

\frac{\partial}{\partial y} (ln (x + y + z))

\frac{5 e ^{- s}}{s + 1}

\int_{0}^{3} π (x)^{2} d x

\int_{1}^{3} 2 π x (\frac{e ^{x}}{x}) d x

\int \frac{1}{X} d X

What is the solution for (y-sqrt((x^2+y^2)))dx-xdy=0 ?
The solution for (y-sqrt((x^2+y^2)))dx-xdy=0 is y=-(x^2}{2e^{c_{1}}}+\frac{e^{c_{1}})/2