What is the derivative of 4tan(x+cot(x)) ?

The derivative of 4tan(x+cot(x)) is 4sec^2(x)-csc^2(x)

What is the first derivative of 4tan(x+cot(x)) ?

The first derivative of 4tan(x+cot(x)) is 4sec^2(x)-csc^2(x)

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\frac{d}{d x} (4 tan (x) + cot (x))

4 sec^{2} (x) - csc^{2} (x)

Solution steps

\frac{d}{d x} (4 tan (x) + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 tan (x)) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (4 tan (x)) = 4 sec^{2} (x)

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 4 sec^{2} (x) - csc^{2} (x)

\frac{\partial}{\partial x} (5 x^{3} y)

(- 41.38, 4.9), (2.38, 3.7)

\frac{d}{d x} (x + \frac{1}{4} sin^{2} (2 x))

f (t) = 1 - 6 t

e^{40 x}

What is the derivative of 4tan(x+cot(x)) ?
The derivative of 4tan(x+cot(x)) is 4sec^2(x)-csc^2(x)
What is the first derivative of 4tan(x+cot(x)) ?
The first derivative of 4tan(x+cot(x)) is 4sec^2(x)-csc^2(x)