What is the derivative of ((4x^2+8x+2)/(sqrt(x))) ?

The derivative of ((4x^2+8x+2)/(sqrt(x))) is (6x^2+4x-1)/(xsqrt(x))

What is the first derivative of ((4x^2+8x+2)/(sqrt(x))) ?

The first derivative of ((4x^2+8x+2)/(sqrt(x))) is (6x^2+4x-1)/(xsqrt(x))

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\frac{d}{d x} (\frac{( 4 x ^{2} + 8 x + 2 )}{x})

\frac{6 x ^{2} + 4 x - 1}{x x}

Solution steps

\frac{d}{d x} (\frac{( 4 x ^{2} + 8 x + 2 )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{2} + 8 x + 2 ) x - \frac{d}{d x} ( x ) ( 4 x ^{2} + 8 x + 2 )}{( x ) ^{2}}

\frac{d}{d x} (4 x^{2} + 8 x + 2) = 8 x + 8

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{( 8 x + 8 ) x - \frac{1}{2 x} ( 4 x ^{2} + 8 x + 2 )}{( x ) ^{2}}

Simplify

\frac{( 8 x + 8 ) x - \frac{1}{2 x} ( 4 x ^{2} + 8 x + 2 )}{( x ) ^{2}} : \frac{6 x ^{2} + 4 x - 1}{x x}

= \frac{6 x ^{2} + 4 x - 1}{x x}

\frac{d}{d x} (\frac{- 3}{x})

\int x (x + 1)^{2} d x

\frac{d y}{d x} = x^{3} (x - x y)

\int \frac{1}{( x + 4 ) ( x - 1 ) ^{2}} d x

\int 5^{s i n (x)} cos (x) d x

What is the derivative of ((4x^2+8x+2)/(sqrt(x))) ?
The derivative of ((4x^2+8x+2)/(sqrt(x))) is (6x^2+4x-1)/(xsqrt(x))
What is the first derivative of ((4x^2+8x+2)/(sqrt(x))) ?
The first derivative of ((4x^2+8x+2)/(sqrt(x))) is (6x^2+4x-1)/(xsqrt(x))