What is the derivative of tan(2x+4) ?

The derivative of tan(2x+4) is sec^2(2x+4)*2

What is the first derivative of tan(2x+4) ?

The first derivative of tan(2x+4) is sec^2(2x+4)*2

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\frac{d}{d x} (tan (2 x + 4))

sec^{2} (2 x + 4) \cdot 2

Solution steps

\frac{d}{d x} (tan (2 x + 4))

Apply the chain rule:

sec^{2} (2 x + 4) \frac{d}{d x} (2 x + 4)

= sec^{2} (2 x + 4) \frac{d}{d x} (2 x + 4)

\frac{d}{d x} (2 x + 4) = 2

= sec^{2} (2 x + 4) \cdot 2

cos (\frac{t}{2})

\frac{d}{d x} (2 x + x)

\frac{\partial}{\partial x} (x^{2} + y^{2} + (21 - x - y)^{2})

\frac{d ^{2} y}{d t ^{2}} - \frac{d y}{d t} + 225 y = 15 sin (15 t)

\int - 2 sin (x) cos (x) d x

What is the derivative of tan(2x+4) ?
The derivative of tan(2x+4) is sec^2(2x+4)*2
What is the first derivative of tan(2x+4) ?
The first derivative of tan(2x+4) is sec^2(2x+4)*2