What is the tangent of f(x)=x^2,(0,-25) ?

The tangent of f(x)=x^2,(0,-25) is y=10x-25 \lor y=-10x-25

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tangent of f(x)=x^2,(0,-25)

tangent of

f (x) = x^{2}, (0, - 25)

y = 10 x - 25 or y = - 10 x - 25

Solution steps

Slope of the tangent line at

(0, - 25) : m = \frac{x ^{2} + 25}{x}

Find the slope of

f (x) = x^{2} : m = 2 x

Solve

2 x = \frac{x ^{2} + 25}{x} : x = 5, x = - 5

Find the tangent line at

x = 5 : y = 10 x - 25

Find the tangent line at

x = - 5 : y = - 10 x - 25

y = 10 x - 25 or y = - 10 x - 25

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f (x) = x^{4} - 18 x^{2} + 81, at x = - 2

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What is the tangent of f(x)=x^2,(0,-25) ?
The tangent of f(x)=x^2,(0,-25) is y=10x-25 \lor y=-10x-25