What is (\partial)/(\partial y)(sin(y)-tan(x)-y) ?

The answer to (\partial)/(\partial y)(sin(y)-tan(x)-y) is cos(y)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(y)-tan(x)-y)

\frac{\partial}{\partial y} (sin (y) - tan (x) - y)

cos (y) - 1

Solution steps

\frac{\partial}{\partial y} (sin (y) - tan (x) - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (sin (y)) - \frac{\partial}{\partial y} (tan (x)) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (sin (y)) = cos (y)

\frac{\partial}{\partial y} (tan (x)) = 0

\frac{\partial}{\partial y} (y) = 1

= cos (y) - 0 - 1

Simplify

= cos (y) - 1

ln (x e^{- 2 x})

\int \frac{x - 2}{x + 2} d x

y = x^{3} - 3 x + 5, (3, 23)

\frac{d}{d t} (5 sin (t) cos (t))

What is (\partial)/(\partial y)(sin(y)-tan(x)-y) ?
The answer to (\partial)/(\partial y)(sin(y)-tan(x)-y) is cos(y)-1