What is the derivative of 3x^2+5x+1 ?

The derivative of 3x^2+5x+1 is 6x+5

What is the first derivative of 3x^2+5x+1 ?

The first derivative of 3x^2+5x+1 is 6x+5

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\frac{d}{d x} (3 x^{2} + 5 x + 1)

6 x + 5

Solution steps

\frac{d}{d x} (3 x^{2} + 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (1) = 0

= 6 x + 5 + 0

Simplify

= 6 x + 5

\int e^{2 x + 3} \cdot sin (4 x) d x

\int x^{2} (x^{3} + 5)^{7} d x

\frac{d}{d x} (x^{12} - 12 e^{x})

f (x) = e^{- 1}

f (x) = x^{8}

What is the derivative of 3x^2+5x+1 ?
The derivative of 3x^2+5x+1 is 6x+5
What is the first derivative of 3x^2+5x+1 ?
The first derivative of 3x^2+5x+1 is 6x+5