What is the integral from 1 to 32 of x^{-9/5} ?

The integral from 1 to 32 of x^{-9/5} is 75/64

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integral from 1 to 32 of x^{-9/5}

\int_{1}^{32} x^{- \frac{9}{5}} d x

\frac{75}{64}

Decimal Notation

1.171875

Solution steps

\int_{1}^{32} x^{- \frac{9}{5}} d x

Apply the Power Rule

: [- \frac{5}{4 x ^{\frac{4}{5}}}]_{1}^{32}

= [- \frac{5}{4 x ^{\frac{4}{5}}}]_{1}^{32}

Compute the boundaries:

\frac{75}{64}

= \frac{75}{64}

(- 9 x^{2} + 4)^{2}

\int \frac{2 x ^{4} + 3 x}{2 x ^{2}} d x

\int \frac{1}{1 + t} d t

\frac{4 x}{x ^{2} + 4}

\int e^{x^{2}} 4 x d x

What is the integral from 1 to 32 of x^{-9/5} ?
The integral from 1 to 32 of x^{-9/5} is 75/64