What is the limit as x approaches 4+of (-3)/(8-2x) ?

The limit as x approaches 4+of (-3)/(8-2x) is infinity

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limit as x approaches 4+of (-3)/(8-2x)

x \to 4 + lim (\frac{- 3}{8 - 2 x})

\infty

Solution steps

x \to 4 + lim (\frac{- 3}{8 - 2 x})

For

x

approaching

4

from the right

, x > 4 \Rightarrow 8 - 2 x < 0

The denominator is a negative quantity approaching 0 from the left

= \infty

\frac{d}{d x} (6 x^{1.5} - 4 x^{0.5})

\frac{\partial}{\partial x} (x e^{- y} + y e^{- x})

e^{t} sin (6 t)

\frac{d}{d x} (sin (x) x)

f (x) = 7 e^{x} + 4 x, at x = 0

What is the limit as x approaches 4+of (-3)/(8-2x) ?
The limit as x approaches 4+of (-3)/(8-2x) is infinity