What is the derivative of 8/(x^3) ?

The derivative of 8/(x^3) is -(24)/(x^4)

What is the first derivative of 8/(x^3) ?

The first derivative of 8/(x^3) is -(24)/(x^4)

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derivative of

\frac{8}{x ^{3}}

- \frac{24}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{8}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 3 x^{- 3 - 1})

Simplify

8 (- 3 x^{- 3 - 1}) : - \frac{24}{x ^{4}}

= - \frac{24}{x ^{4}}

\frac{d}{d x} ((5 x^{3})^{x})

x \frac{d y}{d x} + y = 3 x y

\frac{\partial}{\partial y} (cos (3 x + 4 y))

\frac{d y}{d x} = \frac{3 y}{2 x}

\int ln (9) d x

What is the derivative of 8/(x^3) ?
The derivative of 8/(x^3) is -(24)/(x^4)
What is the first derivative of 8/(x^3) ?
The first derivative of 8/(x^3) is -(24)/(x^4)