What is the d/(dz)(sinh(z+ipi)) ?

The d/(dz)(sinh(z+ipi)) is cosh(z+ipi)

What is the first d/(dz)(sinh(z+ipi)) ?

The first d/(dz)(sinh(z+ipi)) is cosh(z+ipi)

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\frac{d}{d z} (sinh (z + iπ))

cosh (z + iπ)

Solution steps

\frac{d}{d z} (sinh (z + iπ))

Apply the chain rule:

cosh (z + iπ) \frac{d}{d z} (z + iπ)

= cosh (z + iπ) \frac{d}{d z} (z + iπ)

\frac{d}{d z} (z + iπ) = 1

= cosh (z + iπ) \cdot 1

Simplify

= cosh (z + iπ)

\int 6 x + 12 d x

\frac{\partial}{\partial t} (9 cos (t))

\frac{d}{d x} (\frac{x ^{3} ln ( x )}{x + 2})

\int \frac{3}{x x ^{2} - 1} d x

\frac{d}{d x} f (x) = 4 x - 9 x^{2}

What is the d/(dz)(sinh(z+ipi)) ?
The d/(dz)(sinh(z+ipi)) is cosh(z+ipi)
What is the first d/(dz)(sinh(z+ipi)) ?
The first d/(dz)(sinh(z+ipi)) is cosh(z+ipi)