What is the derivative of ln(x^2-4) ?

The derivative of ln(x^2-4) is (2x)/(x^2-4)

What is the first derivative of ln(x^2-4) ?

The first derivative of ln(x^2-4) is (2x)/(x^2-4)

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derivative of

ln (x^{2} - 4)

\frac{2 x}{x ^{2} - 4}

Solution steps

\frac{d}{d x} (ln (x^{2} - 4))

Apply the chain rule:

\frac{1}{x ^{2} - 4} \frac{d}{d x} (x^{2} - 4)

= \frac{1}{x ^{2} - 4} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= \frac{1}{x ^{2} - 4} \cdot 2 x

Simplify

\frac{1}{x ^{2} - 4} \cdot 2 x : \frac{2 x}{x ^{2} - 4}

= \frac{2 x}{x ^{2} - 4}

\int sin (x) (- 8 x cos (2 x)) d x

x \to 0 lim (3 x + 2)

f (x) = \frac{2}{3 x}

2 x e^{- 2 x}

\int \frac{1}{( x ^{2} - 4 ) ^{\frac{3}{2}}} d x

What is the derivative of ln(x^2-4) ?
The derivative of ln(x^2-4) is (2x)/(x^2-4)
What is the first derivative of ln(x^2-4) ?
The first derivative of ln(x^2-4) is (2x)/(x^2-4)