What is the integral from 0 to pi/4 of (sin(x)) ?

The integral from 0 to pi/4 of (sin(x)) is -1/(sqrt(2))+1

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integral from 0 to pi/4 of (sin(x))

\int_{0}^{\frac{π}{4}} (sin (x)) d x

- \frac{1}{2} + 1

Decimal Notation

0.29289 \dots

Solution steps

\int_{0}^{\frac{π}{4}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

- \frac{1}{2} + 1

= - \frac{1}{2} + 1

\frac{d}{d x} (\frac{x}{x + 1})

f (x) = 8 x (x + 2), at x = 3

\int cot^{3} (x) csc^{5} (x) d x

\int sin (2 x) cos^{5} (2 x) d x

What is the integral from 0 to pi/4 of (sin(x)) ?
The integral from 0 to pi/4 of (sin(x)) is -1/(sqrt(2))+1