What is the solution for 4y^{''}-9y=0 ?

The solution for 4y^{''}-9y=0 is y=c_{1}e^{(3t)/2}+c_{2}e^{-(3t)/2}

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4y^{''}-9y=0

4 y^{^{''}} - 9 y = 0

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}}

Solution steps

4 y^{''} (t) - 9 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}}

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}}

y = \frac{1}{t + 1}

\frac{d}{d x} (\frac{1}{4} x^{3} - 2 x)

\frac{d}{d x} (sin (e^{- x}))

x \to \infty lim (\frac{1}{x} + 6)

y^{^{'}} = - 3 (1 - y) (1 - 2 y)

What is the solution for 4y^{''}-9y=0 ?
The solution for 4y^{''}-9y=0 is y=c_{1}e^{(3t)/2}+c_{2}e^{-(3t)/2}