What is the solution for (dy)/(dx)=-y^3 ?

The solution for (dy)/(dx)=-y^3 is y=sqrt(-1/(2(-x+c_{1)))},y=-sqrt(-1/(2(-x+c_{1)))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=-y^3

\frac{d y}{d x} = - y^{3}

y = - \frac{1}{2 ( - x + c _{1} )}, y = - - \frac{1}{2 ( - x + c _{1} )}

Solution steps

\frac{d y}{d x} = - y^{3}

Solve separable ODE:

y = - \frac{1}{2 ( - x + c _{1} )}, y = - - \frac{1}{2 ( - x + c _{1} )}

y = - \frac{1}{2 ( - x + c _{1} )}, y = - - \frac{1}{2 ( - x + c _{1} )}

y = x^{2} - 8 x + 9, (1, 2)

\frac{d}{d x} (u e^{- x})

\int 361 - x^{2} d x

\int - 2 x^{- 1} d x

\int (\frac{e ^{x}}{3} + 2 x) d x

What is the solution for (dy)/(dx)=-y^3 ?
The solution for (dy)/(dx)=-y^3 is y=sqrt(-1/(2(-x+c_{1)))},y=-sqrt(-1/(2(-x+c_{1)))}