What is the tangent of f(x)=cos(x),\at x=pi ?

The tangent of f(x)=cos(x),\at x=pi is y=-1

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tangent of f(x)=cos(x),\at x=pi

tangent of

f (x) = cos (x), at x = π

y = - 1

Solution steps

Find the tangent point:

(π, - 1)

Find the slope of

f (x) = cos (x) : \frac{df ( x )}{d x} = - sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(π, - 1) : y = - 1

y = - 1

\frac{e ^{- 4 s}}{s ( s ^{2} + 16 )}

\frac{d y}{d x} = - 3 y

(6 x + 7)^{x}

\frac{d}{d x} (x^{2} arccos (x))

\int \frac{11 x + 17}{2 x ^{2} + 7 x - 4} d x

What is the tangent of f(x)=cos(x),\at x=pi ?
The tangent of f(x)=cos(x),\at x=pi is y=-1