What is the solution for xy^'+xy-y^'-2y=0 ?

The solution for xy^'+xy-y^'-2y=0 is y=e^{-x+1+c_{1}}x-e^{-x+1+c_{1}}

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xy^'+xy-y^'-2y=0

x y^{^{'}} + x y - y^{^{'}} - 2 y = 0

y = e^{- x + 1 + c_{1}} x - e^{- x + 1 + c_{1}}

Solution steps

x y^{'} (x) + x y - y^{'} (x) - 2 y = 0

Solve separable ODE:

y = e^{- x + 1 + c_{1}} x - e^{- x + 1 + c_{1}}

y = e^{- x + 1 + c_{1}} x - e^{- x + 1 + c_{1}}

\int - 2 tan (2 x) d x

x^{2} y^{^{'}} + x y = 7

x \to 1 + lim (x^{2} + 2 x)

x \to 0 lim (\frac{( sin ( 6 x ) )}{x})

\int \frac{x ^{2} + 9}{x} d x

What is the solution for xy^'+xy-y^'-2y=0 ?
The solution for xy^'+xy-y^'-2y=0 is y=e^{-x+1+c_{1}}x-e^{-x+1+c_{1}}