What is the slope of y=x^2-3x-5,(2,-7) ?

The slope of y=x^2-3x-5,(2,-7) is 1

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slope of y=x^2-3x-5,(2,-7)

slope

y = x^{2} - 3 x - 5, (2, - 7)

1

Solution steps

y = x^{2} - 3 x - 5

In order to find the slope of the function, take the derivative of

x^{2} - 3 x - 5

\frac{d}{d x} (x^{2} - 3 x - 5) = 2 x - 3

2 x - 3

Find the value of

2 x - 3

for

x = 2 : 1

1

f (x) = 3 x^{2} - 12 x + 1, (0, 1)

\frac{d}{d x} (\frac{x ^{3}}{3} - 2 x^{2} - 5 x)

f (x) = x^{2} - 4, at x = 5

n = 0 \sum \infty 3^{- 2 n}

\frac{d}{d x} (ln (3 x e^{- x}))