What is implicit (dy)/(dx),y=ln(x) ?

The answer to implicit (dy)/(dx),y=ln(x) is (dy)/(dx)= 1/x

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implicit (dy)/(dx),y=ln(x)

implicit derivative

\frac{d y}{d x}, y = ln (x)

\frac{d y}{d x} = \frac{1}{x}

Solution steps

y = ln (x)

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = \frac{1}{x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1}{x}

\frac{d y}{d x} = \frac{1}{x}

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 2)^{7})

x \to - 1 - lim (\frac{3}{x + 1})

f^{^{'}} (x) = \frac{5}{6 x ^{5}}

\int \frac{sin ( x ) + cos ( x )}{tan ( x )} d x

\int 6 x^{5} e^{8 x^{6}} d x

What is implicit (dy)/(dx),y=ln(x) ?
The answer to implicit (dy)/(dx),y=ln(x) is (dy)/(dx)= 1/x