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Popular >

y^'=3y+xe^x

Solution

y^{^{'}} = 3 y + x e^{x}

Solution

y = - \frac{e ^{x} ( 2 x + 1 )}{4} + c_{1} e^{3 x}

Solution steps

y^{'} (x) = 3 y + x e^{x}

Solve linear ODE:

y = - \frac{e ^{x} ( 2 x + 1 )}{4} + c_{1} e^{3 x}

y = - \frac{e ^{x} ( 2 x + 1 )}{4} + c_{1} e^{3 x}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=3y+xe^x ?
The solution for y^'=3y+xe^x is y=-(e^x(2x+1))/4+c_{1}e^{3x}