What is the derivative of 2x^3-9x^2+12x-3 ?

The derivative of 2x^3-9x^2+12x-3 is 6x^2-18x+12

What is the first derivative of 2x^3-9x^2+12x-3 ?

The first derivative of 2x^3-9x^2+12x-3 is 6x^2-18x+12

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\frac{d}{d x} (2 x^{3} - 9 x^{2} + 12 x - 3)

6 x^{2} - 18 x + 12

Solution steps

\frac{d}{d x} (2 x^{3} - 9 x^{2} + 12 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (12 x) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (3) = 0

= 6 x^{2} - 18 x + 12 - 0

Simplify

= 6 x^{2} - 18 x + 12

f (x) = \frac{1}{x ^{8}}

\frac{d}{d x} (ln (ln (15 x)))

t sin (π t)

\int_{3}^{4.5} \frac{x}{8} d x

\int \frac{x ^{3}}{x ^{3} + 1} d x

What is the derivative of 2x^3-9x^2+12x-3 ?
The derivative of 2x^3-9x^2+12x-3 is 6x^2-18x+12
What is the first derivative of 2x^3-9x^2+12x-3 ?
The first derivative of 2x^3-9x^2+12x-3 is 6x^2-18x+12