What is the derivative of (y^3)/(27)+9/(4y) ?

The derivative of (y^3)/(27)+9/(4y) is (y^2)/9-9/(4y^2)

What is the first derivative of (y^3)/(27)+9/(4y) ?

The first derivative of (y^3)/(27)+9/(4y) is (y^2)/9-9/(4y^2)

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derivative of

\frac{y ^{3}}{27} + \frac{9}{4 y}

\frac{y ^{2}}{9} - \frac{9}{4 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{y ^{3}}{27} + \frac{9}{4 y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{y ^{3}}{27}) + \frac{d}{d y} (\frac{9}{4 y})

\frac{d}{d y} (\frac{y ^{3}}{27}) = \frac{y ^{2}}{9}

\frac{d}{d y} (\frac{9}{4 y}) = - \frac{9}{4 y ^{2}}

= \frac{y ^{2}}{9} - \frac{9}{4 y ^{2}}

\int \frac{1}{( x + x ^{2} )} d x

\int sin (4 x + 3) d x

\frac{d y}{d x} + y = x + 1

cos (2 x)

y^{^{'}} = \frac{y}{x} - 1

What is the derivative of (y^3)/(27)+9/(4y) ?
The derivative of (y^3)/(27)+9/(4y) is (y^2)/9-9/(4y^2)
What is the first derivative of (y^3)/(27)+9/(4y) ?
The first derivative of (y^3)/(27)+9/(4y) is (y^2)/9-9/(4y^2)