What is the first derivative of 5+4x ?

The first derivative of 5+4x is 4

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derivative of 5+4x

\frac{d}{d x} (5 + 4 x)

4

Solution steps

\frac{d}{d x} (5 + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5) = 0

\frac{d}{d x} (4 x) = 4

= 0 + 4

Simplify

= 4

\frac{\partial}{\partial y} (cos (2 x) sin (3 y))

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (4) = 2, y^{^{'}} (4) = 2

\frac{d}{d x} (tan (x - 5))

\int xg (x^{2}) d x

\int \frac{1}{5 x + 1} d x