What is the tangent of f(x)=(7x)/(x-1),(2,14) ?

The tangent of f(x)=(7x)/(x-1),(2,14) is y=-7x+28

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tangent of f(x)=(7x)/(x-1),(2,14)

tangent of

f (x) = \frac{7 x}{x - 1}, (2, 14)

y = - 7 x + 28

Solution steps

Find the slope of

f (x) = \frac{7 x}{x - 1} : \frac{df ( x )}{d x} = - \frac{7}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{7 x}{x - 1}

(2, 14) : m = - 7

Find the line with slope m=

- 7

and passing through

(2, 14) : y = - 7 x + 28

y = - 7 x + 28

\frac{\partial}{\partial x} (sin (8 x) cos (4 y))

\int_{0}^{1} x (\frac{2 ( x + 1 )}{3}) d x

x \to - 2 - lim (3 x + 6 - 6)

x y^{^{'}} + y = e^{x}

n = 2 \sum \infty \frac{1}{3 ^{n}}

What is the tangent of f(x)=(7x)/(x-1),(2,14) ?
The tangent of f(x)=(7x)/(x-1),(2,14) is y=-7x+28