What is the integral of e^{5x+2} ?

The integral of e^{5x+2} is 1/5 e^{5x+2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{5x+2}

\int e^{5 x + 2} d x

\frac{1}{5} e^{5 x + 2} + C

Solution steps

\int e^{5 x + 2} d x

Apply u-substitution

: \int e^{u} \frac{1}{5} d u

= \int e^{u} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{5} e^{u}

Substitute back

u = 5 x + 2

= \frac{1}{5} e^{5 x + 2}

Add a constant to the solution

= \frac{1}{5} e^{5 x + 2} + C

\frac{\partial}{\partial x} (cos^{6} (x^{9} y^{3}))

\int 9 + 16 x^{2} d x

\frac{\partial}{\partial x} (\frac{3 x - 2 y}{4 x ^{2} + y})

\int_{0}^{l n (5)} e^{x} d x

\frac{d}{d x} (34 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))