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Popular >

area x^2+2,2x+5,[-1,3]

Solution

area

x^{2} + 2, 2 x + 5, [- 1, 3]

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{3} x^{2} + 2 - (2 x + 5) d x

Solve

\int_{- 1}^{3} x^{2} + 2 - (2 x + 5) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

integral from 0 to 1 of 3sqrt(x)-3x

\int_{0}^{1} 3 x - 3 x d x

(dy)/(dx)= 1/x (y^2+0.4y)

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 0.4 y)

integral of (x^2-4x+7)/((x+1)(x^2-2x+3))

\int \frac{x ^{2} - 4 x + 7}{( x + 1 ) ( x ^{2} - 2 x + 3 )} d x

tangent of y=5tan(x)tangent of

y = 5 tan (x)

t^2(dy)/(dt)+ty=4

t^{2} \frac{d y}{d t} + t y = 4

Frequently Asked Questions (FAQ)

What is area x^2+2,2x+5,[-1,3] ?
The answer to area x^2+2,2x+5,[-1,3] is 32/3