What is the solution for sin(x)dx+ydy=0 ?

The solution for sin(x)dx+ydy=0 is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}

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sin(x)dx+ydy=0

sin (x) d x + y d y = 0

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

Solution steps

sin (x) d x + y d y = 0

Solve separable ODE:

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

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\frac{d}{d x} (\frac{a + b x + c x ^{2}}{x})

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What is the solution for sin(x)dx+ydy=0 ?
The solution for sin(x)dx+ydy=0 is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}