integral of 4sin(2x)-3cos(3x)

Lösung

\int 4 \cdot sin (2 x) - 3 \cdot cos (3 x) d x

- 2 cos (2 x) - sin (3 x) + C

Schritte zur Lösung

\int 4 sin (2 x) - 3 cos (3 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 sin (2 x) d x - \int 3 cos (3 x) d x

\int 4 sin (2 x) d x = - 2 cos (2 x)

\int 3 cos (3 x) d x = sin (3 x)

= - 2 cos (2 x) - sin (3 x)

Füge eine Konstante zur Lösung hinzu

= - 2 cos (2 x) - sin (3 x) + C

\int 15 x^{17} e^{x^{9}} d x

x \to 4 lim (3 \frac{x ^{2}}{2})

t an g e n t f (x) = \frac{1}{x ^{5}}, (- 3, - \frac{1}{243})

\int_{1}^{3} x ln (x) d x

\int \frac{4 - 32 x}{25 - 16 x ^{2}} d x