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Popular >

y^'+y=2e^x

Solution

y^{^{'}} + y = 2 e^{x}

Solution

y = e^{x} + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = 2 e^{x}

Solve linear ODE:

y = e^{x} + \frac{c _{1}}{e ^{x}}

y = e^{x} + \frac{c _{1}}{e ^{x}}

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\int \frac{1}{x + 8} d x

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\int_{0}^{1} \frac{2 x}{( x ^{2} + 5 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=2e^x ?
The solution for y^'+y=2e^x is y=e^x+(c_{1})/(e^x)