What is the derivative of e^{4tsin(2t)} ?

The derivative of e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))

What is the first derivative of e^{4tsin(2t)} ?

The first derivative of e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

e^{4 t s i n (2 t)}

e^{4 t s i n (2 t)} \cdot 4 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{4 t s i n (2 t)})

Apply the chain rule:

e^{4 t s i n (2 t)} \frac{d}{d t} (4 t sin (2 t))

= e^{4 t s i n (2 t)} \frac{d}{d t} (4 t sin (2 t))

\frac{d}{d t} (4 t sin (2 t)) = 4 (sin (2 t) + 2 t cos (2 t))

= e^{4 t s i n (2 t)} \cdot 4 (sin (2 t) + 2 t cos (2 t))

\int \frac{x ^{2} + 3}{x ^{2} - 3 x + 2} d x

\int (3 x^{2} + cos (x)) d x

\frac{d}{d x} (e^{3 x s i n (2 x)})

\frac{\partial}{\partial x} (\frac{x}{1 + x ^{2} y ^{2}})

\int x (x + 7)^{6} d x

What is the derivative of e^{4tsin(2t)} ?
The derivative of e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))
What is the first derivative of e^{4tsin(2t)} ?
The first derivative of e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))